##[Cr(NH_3)_6][(NO_3)_3]## Number of elements? Number of atoms per element? Total number of atoms in compound?

Here’s what I got.
You’re actually dealing with a coordination compound called hexamminechromium(III) nitrate, which consists of the hexaamminechromium(III) complex ion, ##”Cr”(“NH”_3)_6^(3+)##, and the nitrate anion, ##”NO”_3^(-)##.
More specifically, the coordination compound consists of one hexamminechromium(III) complex ion and three nitrate anions.
So, how many are a part of this compound? To figure that out, break up the complex ion and the nitrate anion into their respective constituent elements.
Notice that ##6## subscript that follows the ammonia ligands. This means that the complex ion contains six ammonia molecules, ##”NH”_3##, so make sure that you keep track of all these atoms.
You can thus say that ##”Cr”(“NH”_3)_6^(3+)## contains
one chromium atom, ##”Cr”##
six nitrogen atoms, ##”N”##
eighteen hydrogen atoms, ##”H”##
Now focus on the nitrate anion. Notice that it has a ##3## subscript, so keep that in mind when listing the number of atoms it contains.
You can say that three nitrate anions, ##3 xx”NO”_3^(-)##, will contain
three nitrogen atoms, ##”N”##
nine oxygen atoms, ##”O”##
So, this coordination compound contains four distinct elements
chromium
hydrogen
nitrogen
oxygen
Add up all the atoms we’ve listed above to get the total number of atoms per element
chromium: ##1 ->## from the complex ion
hydrogen: ##18 ->## all from the complex ion
nitrogen: ##9 ->## ##6## from the complex ion and ##3## from the three nitrate anions
oxygen: ##9 ->## all from the nitrate anions
The total number of atoms present in the compound will be
##”no. of atoms” = 1 + 18 + 9 + 9 = 37##

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